☞HUNDERD POINT CHALLANGE TO ALL BRAINLY EXPERTS
#FOR MATHS #
o==[]::::::::::::::::> SOLVE FOR X AND Y
:NO FAKE ANSWERS PLEASE
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let 1/√x+y be m and 1√x-y be n
according to the given condition
2m+3n=2.......(1)
4m-9n=-1.......(2)
multiplying eq (1) by 3 n adding with eq(2)
6m+9n=6
+4m-9n=-1
_________
10m=5
m=5/10=1/2
substituting m in eq (1)
2(1/2)+9n=6
1+9n=6
9n=6-1
9n=5
n=5/9
resubstituting the value of m & n
m=1/√x+y ;n=1/√x-y
1/2=1/√x+y ;5/9= 1/√x-y
√x+y=2 ;5√x-y=9
squaring both sides
x+y=4....(3) ; 25x-25y=81.....(4)
multiplying eq 3 by 25 n subtracting with eq (4)
25x+25y=100
+ 25x-25y=81
____________
50x=181
x=181/50
substituting x=181/50 in eq(3)
181/50+y=4
y=4-181/50
y=200-181/50
y=19/50
therefore solution =(x,y)=(181/50,19/50)
i m not sure about the ans but i tried:)
according to the given condition
2m+3n=2.......(1)
4m-9n=-1.......(2)
multiplying eq (1) by 3 n adding with eq(2)
6m+9n=6
+4m-9n=-1
_________
10m=5
m=5/10=1/2
substituting m in eq (1)
2(1/2)+9n=6
1+9n=6
9n=6-1
9n=5
n=5/9
resubstituting the value of m & n
m=1/√x+y ;n=1/√x-y
1/2=1/√x+y ;5/9= 1/√x-y
√x+y=2 ;5√x-y=9
squaring both sides
x+y=4....(3) ; 25x-25y=81.....(4)
multiplying eq 3 by 25 n subtracting with eq (4)
25x+25y=100
+ 25x-25y=81
____________
50x=181
x=181/50
substituting x=181/50 in eq(3)
181/50+y=4
y=4-181/50
y=200-181/50
y=19/50
therefore solution =(x,y)=(181/50,19/50)
i m not sure about the ans but i tried:)
KanishqParashar:
wrong
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