Question

Hundred gram of water has 3 gram of urea dissolved in it calculate the freezing point of solution molar mass of urea is equal to 60 gram per mole

Answer 1

Answer : The freezing point of a solution is 272.07 K.

Solution : Given,

   (for water)

Mass of solute (urea) = 3 g

Volume of solvent (water) = 100 ml

Molar mass of urea = 60 g/mole

Density of water = 1 g/ml

First we have to calculate the mass of solvent.

Mass of solvent = Density of solvent × volume of solvent

Mass of solvent = 1 g/ml × 100 ml = 100 g

Now we have to calculate the molality of solution.

Formula used :

The formula used for depression in freezing point is,

where,

= freezing point of pure solvent =  = 273 K

= freezing point of solution

m = molality

= molal depression constant

Now put all the given values in this formula, we get

Therefore, the freezing point of a solution is 272.07 K.

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