Math, asked by prajwalpandhare08, 10 months ago

hundred metre long train with the speed of 30 km per hour can cross a man in how much time​

Answers

Answered by raj3294
0

Answer:

Step-by-step explanation:

DISTANCE TRAVELLED = LEGTH OF THE TRAIN , D = 100 M

VELOCITY, V = 30 KM/H

                       = 30*5/18

                       = 8.33 M/S

TIME TAKEN , T=?

VELOCITY = DISTANCE / TIME TAKEN

8.33 = 100/ TIME

TIME = 100/8.33

TIME = 12.004 SECONDS.

NOTE :

TO CONVERT KM/ H TO M/S MULTIPLY BY 5/18

TO CONVERT M/S TO KM /H MULTIPLY BY 18/5.

HOPE THIS HELPS.

Answered by Anonymous
2

\bold\red{\underline{\underline{Answer:}}}

\bold{Train \ will \ take \ 11.9 \ seconds}

\bold{to \ cross \ the \ man.}

\bold\blue{Explanation}

\bold{The \ man \ will \ represent \ as \ a \ point}

\bold{Infront \ of \ train.}

\bold{Therefore, \ the \ time \ taken \ by \ train}

\bold{to \ travel \ the \ distance \ same \ as \ it's }

\bold{length \ will \ be \ equal \ to \ time}

\bold{taken \ to \ cross \ a \ man \ by \ the \ train.}

\bold\orange{Given:}

\bold{=>Length \ of \ train= 100 \ m}

\bold{=>Speed=30 \ km h^{-1}}

\bold\pink{To \ find:}

\bold{Time \ taken \ by \ a \ train \ to \ cross \ a \ man.}

\bold\green{\underline{\underline{Solution}}}

\bold{Speed=30 \ km \ h^{-1}}

\bold{1 \ km=1000 \ m}

\bold{\therefore{Speed=30000 \ m \ h^{-1}}}

\bold{Time=\frac{Distance}{Speed}}

\bold{=>Time=\frac{100}{30000}}

\bold{=>Time=0.0033 \ h}

\bold{1 \ hour = 3600 \ seconds}

\bold{\therefore{0.0033 \ h=0.0033×3600 \ seconds}}

\bold{\therefore{Time=11.88 \ seconds}}

\bold{\therefore{Time=11.9 \ seconds(approx)}}

\bold\purple{\tt{\therefore{Train \ will \ take \ 11.9 \ seconds}}}

\bold\purple{to \ cross \ the \ man.}

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