Question

hundred ml of 3 molar H2 S o4 react with hundred ml of 3 molar and enthalpy of neutralization reaction will be​

Answer 1

Answer:

100ml of 3 mol H2SO4=100 mL of 3*2 g equivalent of H2SO4

100ml of 3 mol of NaOH=100 mL of 3*1 g equivalent of NaOH solution

And then 3 g equivalent of NaOH will neutralize 3 g equivalent of H2SO4 while 6 — 3 = 3 g equivalent of H2SO4 will remain interacted.

so far enthalpy released = number of g equivalent x volume of acid or base in liter × standard enthalpy of neutralization.

=3*100/1000*57.3KJ/mol

=17.19KJ/mol