Question

hundred ml of 3 mole H2 S o4 react with hundred ml of 3 mole NaoH enthalpy of neutralization reaction will be​

Answer 1

Answer:

-57.1 Kj.

Explanation:

Since, there is 100ml of the H2SO4 or the acid and 100 ml of NaOH or the base is used which is same amount is used then. According to the equation 100 ml of 3 mol H2SO4 with 100 ml of 3 mole NaOH is mixed.

Since, the enthalpy of neutralisation for equivalent amount of acid and base is the energy evolved as -57.1 Kj. So, for this reaction the enthalpy of neutralisation is -57.1 Kj.