hundred ml of an aqueous solution contains 6.023 into 10 power 21 solute molecules.the solution is diluted to 1 litre.the number of solute molecules present in 10 ml of the dilute solution is
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➡ HERE IS YOUR ANSWER
➡ 100 ml OF AN AQUEOUS SOLUTION CONTAIN 6.023 × 10^21 MOLECULES
➡ THE SOLUTION IS DILUTED TO 1 LITRE OR 1000 ml
➡ THEREFORE, 1000 ml OF THE AQUEOUS SOLUTION CONTAINS
6.023 × 10^21 / 100 × 1000 =
6.023 × 10 ^22 MOLECULES
➡ NOW, 10 ml OF THIS SOLUTION WILL CONTAIN :-
6.023 × 10^22 / 1000 × 10 =
6.023 × 10^19 MOLECULES OF SOLUTE
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♣ HOPE IT HELPS ♣
➡ MARK MY ANSWER BRAINLIEST
--------------------------------------------------------------------------------------------♣♣♣
♣ HI FRIEND ♣
--------------------------------------------------------------------------------------------♣♣♣
➡ HERE IS YOUR ANSWER
➡ 100 ml OF AN AQUEOUS SOLUTION CONTAIN 6.023 × 10^21 MOLECULES
➡ THE SOLUTION IS DILUTED TO 1 LITRE OR 1000 ml
➡ THEREFORE, 1000 ml OF THE AQUEOUS SOLUTION CONTAINS
6.023 × 10^21 / 100 × 1000 =
6.023 × 10 ^22 MOLECULES
➡ NOW, 10 ml OF THIS SOLUTION WILL CONTAIN :-
6.023 × 10^22 / 1000 × 10 =
6.023 × 10^19 MOLECULES OF SOLUTE
--------------------------------------------------------------------------------------------♣♣♣
♣ HOPE IT HELPS ♣
➡ MARK MY ANSWER BRAINLIEST
taz123:
the answer in my key is same
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