Hundred ml of o2 gas diffuses in 10 seconds hundred ml of gas execution in 30 seconds gas x and time t can be
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Answer:
By Graham's law of diffusion:
Rate of Oxygen / Rate of X = √(MMX/MMO₂)
MMO₂ = 32
Rate of oxygen = 100/10 = 10
Rate of X = 100/T
10 × T/100 = 10T/100
1/10T = √(MMX/32)
1/100T² = MMX/32
MMX = 32/100T²
This is one equation with 2 unknowns. That is T and MMX.
It's a diophantine equation with several solutions:
These solutions could be.
T.......MMX
5.......8
15.....72
20....128
25....200
30....288
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Hundred ml of o2 gas diffuses in 10 seconds hundreds ml of gas execution in 30 seconds gas x and time t can be..........
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