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construct a line parallel to AB and CD from E to F .
now,
ang.AEF + ang.EAB =180
=> ang.AEF + 140 =180
=> ang.AEF= 40
SIMILARLY ang.CEF= 55
NOW, ang. AEC= ang. AEF +ang. CEF
=> ang. AEC =95
now,
ang.AEF + ang.EAB =180
=> ang.AEF + 140 =180
=> ang.AEF= 40
SIMILARLY ang.CEF= 55
NOW, ang. AEC= ang. AEF +ang. CEF
=> ang. AEC =95
Answered by
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x =95 .......
this answer will help you.....
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