Math, asked by nidhiakara, 8 months ago

HURRY GUYS.....i will mark as brainliest if u solve HIS
ΣⁿCₓ ⁿ⁻¹Cₓ from x = 0 to n

Answers

Answered by amiteshkumar71
0

Answer:

(5^n/25)*(3^2n/27)=135

(5^n)*(3^2n)=135*25*27

(5^n)*(3^2n)=5*27*25*27

(5^n)*(3^2n)=(5^3)*(3^6)

Comparing on both sides

n=3

Step-by-step explanation:

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