HURRY GUYS.....i will mark as brainliest if u solve HIS
ΣⁿCₓ ⁿ⁻¹Cₓ from x = 0 to n
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Answer:
(5^n/25)*(3^2n/27)=135
(5^n)*(3^2n)=135*25*27
(5^n)*(3^2n)=5*27*25*27
(5^n)*(3^2n)=(5^3)*(3^6)
Comparing on both sides
n=3
Step-by-step explanation:
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