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v*cosX = 90 ------(1)
v*sinX = 72 ------(2)
Using (1) and (2) we get,
v = 115.25 km/hr
x= tan-1(0.8) = 38.66o
So with respect to signal man standing near to rail track train B is moving with speed 115.25 km/hr at an angle of 38.66o west of north.
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