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If x+y+z = 10. And, x²+y²+z² = 40. Find xy+yz+zx = ???
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x + y + z = 10 it is given______________ 1)
x²+y²+z² = 40 it is also given______________2)
on squaring both side of eq 1) we got
(x + y + z)² = (10)²
x²+y²+z² + 2xy + 2yz + 2xz = 100
on substituting value we got
40 + 2xy + 2yz + 2xz = 100
2xy + 2yz + 2xz = 100 - 40
2xy + 2yz + 2xz = 60
2(xy + yz + xz) = 60
xy + yz + xz = 60/2
xy + yz + xz = 30
hope i help u vibhu
x²+y²+z² = 40 it is also given______________2)
on squaring both side of eq 1) we got
(x + y + z)² = (10)²
x²+y²+z² + 2xy + 2yz + 2xz = 100
on substituting value we got
40 + 2xy + 2yz + 2xz = 100
2xy + 2yz + 2xz = 100 - 40
2xy + 2yz + 2xz = 60
2(xy + yz + xz) = 60
xy + yz + xz = 60/2
xy + yz + xz = 30
hope i help u vibhu
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