Question

HW: 63 If the DNA fragment of length 102A
has 8 adenines, what is the number of G = C
pairs in the DNA fragment?
(a) 8
(b) 16
(d) 22
(c) 44​

Answer 1

Answer:

Here, the given DNA measure = 6.8nm = 68 Angstroms.

Length of DNA = Distance between base pairs × Total number of base pairs

Therefore, 68  

A

˚

 = 3.4  

A

˚

 × Total number of nitrogen base pairs.

Hence, nucleotides = 40

1 nucleotide = 1 nitrogen base + 1 pentose sugar + 1 phosphate groups

So, pentose sugar = 40

Phosphate groups = 40

From the percent mentioned these are 8 combinations of A-T and 12 combinations of C=G in given fragment of DNA. Adenine is paired to thymine by two hydrogen bonds and cytosine is paired to guanine by three hydrogen bonds.

So 8× 2 = 16 and 12 × 3 = 36

16+ 36 = 53 hydrogen bonds.

Explanation:

hope it Helps!