Question

Hw question

Q.1 calculate work done when a force of 5N is acting at 30 degree. And this force is

displacing the object 5m horizontallyHw question
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Answer 1

Answer:

see the attachment

Explanation:

hope the answer will help you

Answer 2

Answer:

21.65 J

Explanation:

Given,

Force= 5 N

Displacement=5 m

Angle between force vector and displacement vector=30°

Hence, work done= force * displacement* cos theta

= 5*5*cos 30 =25*√3/2= 25*1.732/2=43.3/2=21.65 J

Answer: Work done is 21.65 J