Question

hy..........................

Answer 1

Answer:

0

Step-by-step explanation:

Given Equation is sin⁻¹(1 - x) - 2 sin⁻¹x = π/2

⇒ -2 sin⁻¹x = π/2 - sin⁻¹(1 - x)

⇒ -2 sin⁻¹x = cos⁻¹(1 - x)

Let sin⁻¹x = p, we get

⇒ -2p = cos⁻¹(1 - x)

Taking cos on both sides, the above implies.

⇒ cos(-2p) = (1 - x)

⇒ cos(2p) = (1 - x)

⇒ 1 - 2sin²p = (1 - x)

⇒ 1 - 2x² = 1 - x

⇒ 1 - 1 + x - 2x² = 0

⇒ x - 2x² = 0

⇒ x(1 - 2x) = 0

⇒ x = 0, x = 1/2.

But x = 1/2 does not satisfy the given equation.

∴ x = 0 is the solution of the given equation.

Hope it helps!

Answer 2

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