Question

hy bro and sister please give me answer

in this pic your question and chapter name is linear equations in one variable OK plese give me a answer

Answer 1

12) Given sum of the digits is 12
Let the digits in ones place be x
Hence the digit in tens place is (12 – x)
The original number = 10(12 – x) + x = 120 – 9x
Number formed by reversing the digits = 10x + (12 – x)  =  9x + 12

Given that number formed by reversing the digits is 54 greater than the original number.
⇒ 9x + 12 = (120 – 9x) + 54 = 174 – 9x
⇒ 18x = 174 – 12 = 162
∴ x = 9
The original number = 120 – 9x = 120 – 9(9) = 39

13)

Answer 2

12. SUM OF DIGITS OF A TWO DIGIT NUMBER IS 12 . ON ENTER CHANGING THEIR DIGITS NEW NUMBER FORMED WILL BE 54 MORE THAN ORIGINAL NUMBER . FIND ORIGINAL NUMBER .

13. ONE DIGITS IS FOUR TIMES OF OTHER DIGITS IN TWO DIGITS NUMBER. ON ADDING THIS NUMBER TWO NUMBER FORMED BY REPLACING ITS DIGITS SUN WILL BE 110 . FIND THE NUMBER.

= later the tens place digit be a

And unit place digit be b

According to first condition

b=4a---------(1)

according to second condition

3a + b +10B + a = 110

==>11a + 11b =110

a+b = 10

a+4a =10 ( using equation 1)

5a = 10

a = 2

b =8

Required number 28 and 82.

Hope this answer will help u