Question

Hy friends solve this question
$3 \sqrt{12} \times 6 \sqrt{4}$
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Answer 1

Solution :

For solving these kind of questions,First of all we've to break the numbers in their simple Form.

We have :

$\longmapsto \sf \: 3 \sqrt{12} \times 6 \sqrt{4}$

We can write :

$\star \sf \: \sqrt{12} \: as \: \sqrt{2 \times 2 \times 3} = 2 \sqrt{3}$

$\star \sf \: \sqrt{4} \: as \: \sqrt{2 \times 2} = 2$

Put the values :

$\longmapsto \sf \: 3(2 \sqrt{3)} \times 6(2)$

$\longmapsto \sf \: 6 \sqrt{3} \times 12$

Now,Multiply 12 and 6 and keep √3 apart

$\longmapsto \sf \: 6 \times 12 \sqrt{3}$

$\longmapsto \sf \large \boxed{ \purple{ \sf 72 \sqrt{3} }}$

Hence,Required value is 72√3

Answer 2

$\huge\underline\mathscr\blue{SoLuTion}$

$\implies 3 \sqrt{12} \times 6 \sqrt{4} \\ \\ \implies \: 3 \sqrt{2 \times 2 \times 3} \: \: \times 6 \sqrt{2 \times 2} \\ \\ \implies \: 3 \times 2 \sqrt{3} \: \times 6 \times 2 \\ \\ \implies \: 3 \times 6 \times 2 \times 2 \sqrt{3} \\ \\ \implies \: 72 \sqrt{3}$