hy I want question no. 4 with full explanation
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Heya mate, Here is ur answer
Given: 1)BX perpendicular POQ
so, angle POB=angle QOB=90°
2)BX bisect angle ABC
so, angle PBO=angle QBO
To prove:PO=OQ
Proof:In ∆POB and ∆QOB
Angle POB=angle QOB (each 90°,given)
Angle PBO=Angle QBO (Given)
OB=OB(common line)
So, ∆POB congruent ∆QOB(By RHS congruence criterion)
Therefore,PO=OQ(By CPCT)
Hence,Proved.
warm regards
@Laughterqueen
◦•●◉✿[Tʜᴀɴᴋ ʏᴏᴜ]✿◉●•◦
Be Brainly ✌✌✌
Given: 1)BX perpendicular POQ
so, angle POB=angle QOB=90°
2)BX bisect angle ABC
so, angle PBO=angle QBO
To prove:PO=OQ
Proof:In ∆POB and ∆QOB
Angle POB=angle QOB (each 90°,given)
Angle PBO=Angle QBO (Given)
OB=OB(common line)
So, ∆POB congruent ∆QOB(By RHS congruence criterion)
Therefore,PO=OQ(By CPCT)
Hence,Proved.
warm regards
@Laughterqueen
◦•●◉✿[Tʜᴀɴᴋ ʏᴏᴜ]✿◉●•◦
Be Brainly ✌✌✌
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