Question

hy please solve it correct answer will be brainliest​

Answer 1

Answer:

I think it is a square .

so x = 62°

Angle 1 = 28°

I hope it is the corect answer .

Answer 2

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Angle 1 = ${28}^{\circ}$

x = ${62}^{\circ}$

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Since ABCD is a square, all angles at the corners are 90°.

So,

$\sf \angle \: B$ = 90°

$\sf \angle \: B$ = (x + 28)°

Therefore,

x° + 28° = 90°

x° = 62°

To find Angle 1, there are two ways:

Let angle 1 be y.

Way 1:

In square ABCD, there are two triangles.

In triangle ABD,

We know that sum of all angles in a triangle is 180°.

y + x + 90° = 180°

y + 62° = 90° [ x = 62° from above]

y = 28°

Way 2:

We know that, from interior alternate angle y and 28° are equal.

So, y = 28°

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