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The reaction
Br2 + CH Br → CH,Br2 + HBr was
carried out. Which of the following
mechanism steps is productive, but rela-
tively unlikely to occur?
Answers
Explanation:
The reaction Br2 + CH3Br -> CH2Br2 + HBr was carried out. Which of the following mechanism steps is productive , but relatively unlikely to occur? a.) Br* + CH3Br -> HBr + *CH2Br b.) Br* + *CH2Br -> CH2Br2 c.) Br* + Br2 -> Br2 + Br* d.) Br* + *CH3 -> CH3Br
Answer: The mechanism for the reaction Br2 + CH3Br → CH3 + HBr can be described as follows:
Initiation: Br2 molecules collide with CH3Br and form a complex.
Propagation: The complex breaks down to form a Br radical and a CH3 radical.
Chain propagation: The Br radical reacts with CH3Br to form HBr and a new CH3 radical.
Chain termination: The CH3 radical reacts with a Br radical to form CH3Br.
The productive but relatively unlikely step in this mechanism is step 4, the chain termination step because it requires a collision between two highly reactive radicals, which is a relatively unlikely event. This means that the chain reaction will continue until all the reagents are used up or some other termination mechanism takes place.
In conclusion, the most productive but relatively unlikely step in the reaction Br2 + CH3Br → CH3 + HBr is the chain termination step.
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