Question

hyberdisation in CH3CL2

Answer 1

Answer:

Sp3 hybridization

Explanation:

Answer 2

Answer:

Hybridisation = number of sigma bonds + lone pair. CH3Cl = 3 sigma bonds between C & H and 1 between C and Cl There is no lone pair as carbon has 4 valence electrons and all of them have formed a bond (3 with hydrogen and 1 with Cl). Now, hybridisation = (3+1) + 0= 4 = sp3 (1 s & 3 p).

Explanation:

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