hybridisation of Al2(oh)6
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Consider the structure of Al
2
Me
6
compound and find the value of
z
x−y
, where:
x= Maximum number of atoms that can lie in plane having terminal (Al−Me) bonds.
y= Total number of 3c−2e
−
bonds.
z= Total number of atoms that are sp
3
hybridized.
HARD
ANSWER
Have 2 3C−2e bonds ( y = 2 )
Number of atoms lying on a plane having terminal are = ( x = 10 )
Number of sp
3
hybridised atoms are = ( z = 8 )
So value of
z
x−y
=
8
10−2
=1
Answered by
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Answer:
Hybridization of Aluminium is Sp^3 d^2.
[Al (H2O)6)]^+3. In this compound the valency of aluminium "Al" is +3. At normal conditions Aluminium can not exit with valency more than 3.
Explanation:
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