Question

hybridisation of Cocl2 structure
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Answer 1

Answer:

H2O has a tetrahedral arrangement of the electron pairs about the O atom that requires sp3 hybridization. Two of the four sp3 hybrid orbitals are used to form bonds to the two hydrogen atoms, and the other two sp3 hybrid orbitals hold the two lone pairs on oxygen.

Answer 2

The hybridization of $COCl_2$  is, $sp^2$

Explanation :

Formula used  :

$\text{Number of electron pair}=\frac{1}{2}[V+N-C+A]$

where,

V = number of valence electrons present in central atom

N = number of monovalent atoms bonded to central atom

C = charge of cation

A = charge of anion

Now we have to determine the hybridization of the given molecule.

The given molecule is, $COCl_2$

$\text{Number of electrons}=\frac{1}{2}\times [4+2]=3$

The number of electron pair are 3 that means the hybridization will be $sp^2$ and the electronic geometry of the molecule will be trigonal planar.

Hence, the hybridization of $COCl_2$  is, $sp^2$

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