hybridisation of SF4 in this formula Hybridization=1/2(valency electron in central atom+no. Of atom attached to central atom by single bond+negative charge-positive charge).
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10
This one helped me a lot!!
It is 0.5(V+M-C+A)
V= No. Of valence electrons of central atom
M- No. Of monovalent atom
C- Total Cation charge
A- Total Anion charge
For eg:-
CH4
So CH4 has central atom carbon which has four valence electrons and it has 4 monovalent hydrogen atom. As there is no plus or minus charge on compound so
0.5(4+4)= 4
2) SO4^2-
The central atom is sulphur with 6 valence electrons. It has no monovalent atom. The total Anion charge is 2
So 0.5(6+2)- 4
Now match the number you get with:-
Sp- 2
Sp2-3
Sp3-4
Sp3d-5
Sp3d2- 6 and so on
The above two species hence have sp3 hybridisation.
hope it help❤️❤️❤️❤️❤️❤️❤️❤️
It is 0.5(V+M-C+A)
V= No. Of valence electrons of central atom
M- No. Of monovalent atom
C- Total Cation charge
A- Total Anion charge
For eg:-
CH4
So CH4 has central atom carbon which has four valence electrons and it has 4 monovalent hydrogen atom. As there is no plus or minus charge on compound so
0.5(4+4)= 4
2) SO4^2-
The central atom is sulphur with 6 valence electrons. It has no monovalent atom. The total Anion charge is 2
So 0.5(6+2)- 4
Now match the number you get with:-
Sp- 2
Sp2-3
Sp3-4
Sp3d-5
Sp3d2- 6 and so on
The above two species hence have sp3 hybridisation.
hope it help❤️❤️❤️❤️❤️❤️❤️❤️
Answered by
17
hope u get the solution....
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patilp:
hybridization will b same
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