Chemistry, asked by poulami27, 1 year ago

hybridisation of SF4 in this formula Hybridization=1/2(valency electron in central atom+no. Of atom attached to central atom by single bond+negative charge-positive charge). 

Answers

Answered by Rode54
10
This one helped me a lot!!

It is 0.5(V+M-C+A)

V= No. Of valence electrons of central atom

M- No. Of monovalent atom

C- Total Cation charge

A- Total Anion charge

For eg:-

CH4

So CH4 has central atom carbon which has four valence electrons and it has 4 monovalent hydrogen atom. As there is no plus or minus charge on compound so

0.5(4+4)= 4

2) SO4^2-

The central atom is sulphur with 6 valence electrons. It has no monovalent atom. The total Anion charge is 2

So 0.5(6+2)- 4

Now match the number you get with:-

Sp- 2

Sp2-3

Sp3-4

Sp3d-5

Sp3d2- 6 and so on

The above two species hence have sp3 hybridisation.

hope it help❤️❤️❤️❤️❤️❤️❤️❤️
Answered by patilp
17
hope u get the solution....
Attachments:

patilp: hybridization will b same
patilp: but in place of lone pair there will b double bonded oxygen atom
patilp: understood?
poulami27: os means osmium
poulami27: not oxygen
patilp: ok i thought its oxygen
patilp: ok then wait again
poulami27: this is osmium tetraflurid
poulami27: yes
poulami27: btw thankyou for help
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