Hybridisation structure of xef4
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d2sp3----Square Planar.
No. of monovalent atoms around central atom = 4
No. of Valence electrons in central atom = 8
H = (1/2)×(8+4) = 6 = sp3d2 or d2sp3
The two lone pairs are in axial position and the 4 fluorine atoms in the equatorial plane, making the molecule XeF4, Square Planar and hence d2sp3
No. of monovalent atoms around central atom = 4
No. of Valence electrons in central atom = 8
H = (1/2)×(8+4) = 6 = sp3d2 or d2sp3
The two lone pairs are in axial position and the 4 fluorine atoms in the equatorial plane, making the molecule XeF4, Square Planar and hence d2sp3
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Solution is here valence electron of xenon=8
Valence electron of flourine=7
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