Question

hybridization is present
in MX4 (M = element of Group 14)​

Answer 1

Answer:

sp3

Explanation:

it has sp3 hybridization for any mx4 compound

Answer 2

Answer:

M => Element of Group 14 So M has 4 electrons in its outermost shell hence it has to lose 4 electrons or gain 4 electrons to complete octet. Hybridisation present in MX4 => 1/2(4+4+0) => 4 =>

$s {p}^{3}$

is type of hybridisation present in MX4. Hope it helps you.