hybridization of (cr(nh3)6)cl3
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The oxidation state of Cr is +3
The configuration of Cr is : [Ar]3d^5 4s^1
The outermost configuration of Cr^+3 is : 3d^3 4s^0 .
Thus only 2 vacant d orbitals r left so the configuration of the complex is d^2sp^3.
The complex is paramagnetic, octahedral and has magnetic moment of √15.
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