Chemistry, asked by chanchalhello123, 11 months ago

hybridization of [mn( cn)6]3-​

Answers

Answered by Jasleen0599
13

The hybridization of [Mn(CN)₆]³⁻ is d²sp³.

- Here, Mn is in +3 oxidation state.

- The outer electronic configuration of Mn³⁺ = 3d⁶, 4s⁰, 4p⁰

- As CN⁻ is a strong field compound, it will pair up the electrons in 3d orbital.

- So, there are 2 vacant 3d orbitals.

- These two orbitals of 3d subshell, one 4s orbital and three 4p orbitals undergo hybridization.

- Hence the hybridization is d²sp³ and the inner orbital complex [Mn(CN)₆]³⁻ is formed.

Answered by nariyalchampa
3

Explanation:

d²sp³ is

the hybridisation

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