hybridization of [mn( cn)6]3-
Answers
Answered by
13
The hybridization of [Mn(CN)₆]³⁻ is d²sp³.
- Here, Mn is in +3 oxidation state.
- The outer electronic configuration of Mn³⁺ = 3d⁶, 4s⁰, 4p⁰
- As CN⁻ is a strong field compound, it will pair up the electrons in 3d orbital.
- So, there are 2 vacant 3d orbitals.
- These two orbitals of 3d subshell, one 4s orbital and three 4p orbitals undergo hybridization.
- Hence the hybridization is d²sp³ and the inner orbital complex [Mn(CN)₆]³⁻ is formed.
Answered by
3
Explanation:
d²sp³ is
the hybridisation
Similar questions