Question

hybridization of pCl5

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Answer 1

Answer:

Hybridisation of a molecule can be calculated by using the formula:

H = 0.5 × (V + M - C + A)

where, H → Hybridisation; V → Number of Valence Electrons of Free Central Atom; M → Number of Monovalent atoms linked to the central atom; C → Charge on Cation; A → Charge of Anion

After getting a numerical value, you can use the following list for finding out the hybridisation of the required molecule:

2 → sp Hybridisation

3 → sp2 Hybridisation

4 → sp3 Hybridisation

5 → sp3d Hybridisation

6 → sp3d2 Hybridisation

So, for PCl5, where P is the central atom and Cl is the Monovalent atom linked to P,

H = 0.5 × (5 + 5 – 0 + 0) = 0.5 × 10 = 5

So, from the above list, we can deduce that the hybridisation of PCl5 is sp3d.

Explanation:

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