Question

hybridization shown by [Co(NH3)4Cl2​

Answer 1

Answer:

In the presence of NH3 a strong ligand, the 3d electrons pair up leaving two d-orbitals empty. Hence, the hybridization is d2sp3 forming an inner orbital octahedral complex. In [Ni (NH3)6]2+, Ni is in +2 oxidation state with the configuration 3d8. In presence of NH3, the 3d electrons do not pair up.