Question

hydraulic automobile is designed to lift cars with the maximum mass of 3000 kg the area of the Piston carry the load is 425 CM square what maximum pressure would the smaller Piston have to be here

Answer 1

Answer:

Explanation:

ANSWERED BY FIITJEE STUDENT

here given,

Mass equal to 3000 kg

Area equal to 425 cm sq =0.0425 m sq

So , force = mass × acceleration due to gravity

= 3000 kg× 10m/s sq

= 30000N

Force / area = Force 1/ area1. ( Pascale 's formula)

30000/0.0425. = You have not given the value WTF?

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