hydrazine can be used as fuel cell N2H4+O2=N2+2H2O.If delta^0 G for a reaction is -600kJ what will be the E^0 for cell?
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Answered by
9
Hello dear,
● Answer-
∆E°cell = 0.0062 V
● Explaination-
# Given-
∆G° = -600 kJ
∆E°cell = ?
F = 96485 C
# Solution-
In the reaction,
N2H4+O2 ---> N2+2H2O
n = 1
Formula for calculation of ∆E° is -
∆G° = -n × F × ∆E°cell
∆E°cell = -∆G° / (n × F)
∆E°cell = -(-600) / (1 × 96485)
∆E°cell = 0.0062 V
Thus electric potential of hydralazine cell is 0.0062 V.
Hope this is useful.
Keep asking...
● Answer-
∆E°cell = 0.0062 V
● Explaination-
# Given-
∆G° = -600 kJ
∆E°cell = ?
F = 96485 C
# Solution-
In the reaction,
N2H4+O2 ---> N2+2H2O
n = 1
Formula for calculation of ∆E° is -
∆G° = -n × F × ∆E°cell
∆E°cell = -∆G° / (n × F)
∆E°cell = -(-600) / (1 × 96485)
∆E°cell = 0.0062 V
Thus electric potential of hydralazine cell is 0.0062 V.
Hope this is useful.
Keep asking...
Answered by
39
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