Question

Hydrocarbon a on chlorination give b which on heating with alcoholic koh changes into c letter decolourises baeyer's reagent and on ozonolysis form formaldehyde a is

Answer 1

The hydrocarbon 'a' is ethane.

Ethane on chlorination, gives 1-chloroethane, which reacts with alcoholic KOH to give a dehydro-halogenation product (Ethene). The ethene formed from this undergoes ozonolysis to break the double bond and form two molecules of formaldehyde.

'a' - Ethane
'b' - 1-chloroethane
'c' - Ethene

Answer 2

ethane is your answer......