Question

Hydrogen and carbon dioxide gases are mixed at 800k. A reversible reaction takes place. H2(g) + co2(g) h2o(g) + co(g) at equilibrium, the partial pressures of h2 and co2 are both 10.0 kpa. Kp is 0.288 at 800k. What is the partial pressure of co in the equilibrium mixture?

Answer 1

Answer : The partial pressure of $CO$ is, 5.366 KPa

Solution :

The given equilibrium reaction is,

$H_2(g)+CO_2(g)\rightleftharpoons H_2O(g)+CO(g)$

Let the partial pressure of $H_2O$ and $CO$ will be, 'x'

The expression of $K_p$ will be,

$K_p=\frac{(p_{CO})(p_{H_2O})}{(p_{H_2})(p_{CO_2})}$

Now put all the values of partial pressure, we get

$0.288=\frac{(x)\times (x)}{(10)\times (10)}$

By solving the term x, we get

$x=5.366$

The partial pressure of $CO$ = x = 5.366 KPa

Therefore, the partial pressure of $CO$ is, 5.366 KPa