Question

Hydrogen and oxygen combine in the ratio of 1:8 by mass to form water. What mass of hydrog
gas would be required to react completely with 32 g of oxygen gas?​

Answer 1

Answer:

8 g of oxygen reacts with = 1 g of hydrogen

∴ 32 g of oxygen reacts with = (1× 32)/8 = 4 g of hydrogen

Thus, 4 g of hydrogen gas would be required to react completely with 32 g of oxygen gas.

Explanation:

Answer 2

Answer:

hey mate when the hydrogen and oxygen in water are in 1:8 ....... then

as,

1g of hydrogen : 8 g of oxygen

? : 32g of oxygen

= 1/8*32

= 4g

VERIFICATION :-

THE SIMPLEST RATIO SHOULD BE 1:8

SO as 4/32 is a equivalent fraction of 1/8

hence the required answer for hydrogen molecule in 32 g of O2 is 4g....