Question

Hydrogen and oxygen combine in the ratio of 1 : 8 by mass to form water. What mass of oxygen gas would be required to react completely with 3 g of hydrogen gas?

Answer 1

Ratio of H : O by mass in water is:

Hydrogen : Oxygen —> H2O

∴ 1 : 8 = 3 : x

x = 8 x 3

x = 24 g

∴ 24 g of oxygen gas would be required to react completely with 3 g of hydrogen gas.

Answer 2

Given

Hydrogen and oxygen combine in the ratio of 1 : 8 by mass to form water :-

• Hydrogen : Oxygen = 1 : 8

We Find

• Mass of gas would be required to react completely with 3 g of hydrogen gas.

We Know

According to condition :-

$\sf \boxed {\red{ hydrogen\:(H2) : oxygen \:(O2) = H2O}}$

Now, According to the question

1 g of hydrogen reacts with = 8 g of oxygen

So, 3 g of hydrogen reacts with :-

= 8 × 3 = 24 g of oxygen

Hence, 24 g oxygen gas would be required to react completely with 3 g of hydrogen gas.

Required Information

☞ ( H2 + O2 = H2O ) is Chemical Equation balancer.

☞ Hydrogen peroxide is a chemical compound with the formula H2O2.

☞ In its pure form, it is a very pale blue liquid, slightly more viscous than water.

☞ Hydrogen peroxide is the simplest peroxide (a compound with an oxygen–oxygen single bond).