Question

Hydrogen atom initially in the ground state is excited by absorbing a photon of wavelength 980 angstrom the radius of the atom in the excited state in terms of bohr radius a lot will be

Answer 1

i don't know please give me 5points

Answer 2

Answer:

The radius of the atom in the excited state in terms of Bohr radius a lot will be 8.464 angstrom.

Explanation:

Z for hydrogen = 1

$n_{i}=1,n_f=n$

$\frac {1}{\lambda }=R[\frac{1}{n_{i}^2}-\frac{1}{n_{f}^2}]$

$\frac{1}{980\times 10^{-10}m}=1.097\times 10^7 m^{-1}[\frac{1}{1^2}-\frac{1}{n^2}]$

$n = 3.77 \approx 4$

Bohr radius of 4th energy level :

$r_n=0.0529\frac{n^2}{Z}$

$r_4=0.0529 nm\times\frac{16}{1}=0.8464 nm=8.464 \AA$

The radius of the atom in the excited state in terms of Bohr radius a lot will be 8.464 angstrom.