Question

Hydrogen evolved at NTP on complete reaction of 27 gm of Al with excess of aq NaOH would be
(Chemical reaction: 2AI + 2NaOH + 2H20→ 2NaAlO2 + 3H2)
(A) 22.4 lit
(B) 44.8 lit
(C) 67.2 lit
(D) 33.6 lit​

Answer 1

Answer:

Hey!☺️

The chemical reaction is

2Al + 2NaOH + 2H2O → 2NaAlO2 + 3H2

Atomic mass of H2 = 27

For 2x27 the H2 liberated is 3x22.4 L as at STP 1 mole of H2 is 22.4 L

So,

2.7 g Al liberates 2.7x3x22.4/2x27 = 3.36 L H2

Hope it will be helpful ✌️

Answer 2

Explanation:

Aloha !

Hydrogen evolved at NTP on complete reaction of 27 gm of Al with excess of aq NaOH would be

(Chemical reaction: 2AI + 2NaOH + 2H20→ 2NaAlO2 + 3H2)

(A) 22.4 lit

(B) 44.8 lit

(C) 67.2 lit

(D) 33.6 lit✔️✔️✔️✔️✔️

Thank you

@ Twilight Astro ✌️☺️♥️