- Hydrogen Gas expound adiabatically find the pressure when volume
comes double?
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Answer:
P' = 1/2(P)
Explanation:
We know that
PV = nRT
P = pressure of the gas
V = volume of the gas
n = no. of moles
R = ideal gas constant
T = temperature
In case of Hydrogen expanding adiabatically ,
n = 1
Before expansion
Pressure
P = nRT/V
P = RT/V
No change in temperature
When volume comes double i.e.
V' = 2V
The pressure will be
P'V' = nRT
P' = nRT/V'
P' = RT/2V ( n = 1)
P' = 1/2(P)
Pressure after expansion equal to half of pressure before expansion
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