Question

Hydrogen gas is filled in two
identical bottles, A and B, at the
same temperature. The mass of
hydrogen in the two bottles is 12
gm and 48 gm respectively. In
which bottle will sound travel
faster? How may times as fast as
the other?

guys please solve this numericals
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Answer 1

Answer:

this is your answer diii...

hope it helps you.....

Answer 2

Answer:

d. The velocity of sound in gas is related to density of gas as

v∝1ρ√v∝1ρ .....(i)

and the velocity of sound in gas is related to temperature of gas as

v∝T−−√v∝T .....(ii)

Combining (i) and (ii), we get

v∝T√ρ√v∝Tρ

Now, the two bottles given are identical i.e. the volumes of gases are same. Let the volume of the bottle be V. Let M1 and M2 be the masses of the gases in bottles A and B, respectively and v1 and v2 be the velocity of the sound in the two bottles, respectively. Since, the temperature of gas in both the bottles are same, let that common temperature be T. Therefore,

v1v2=M2V√T√M1V√T√=48√12√=2–√⇒v1=2v2v1v2=M2VTM1VT=4812=2⇒v1=2v2

Thus, the sound travels 2 times faster in bottle B as compared to bottle A.