Question

hydrogen gas is prepared in the laboratory by reacting dilute hcl with granulated zinc following reaction take place.Zn+2hcl-zncl2+h2 calculate the volume of hydrogen gas liberated at stp when 32.65g of zinc rezcts with hcl.1mol of gas occupied22.7Lv volume at stp;atomic mass of Zn=65.3u

Answer 1

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Explanation:

Zn+2HCl→ZnCl2+H2

​Molar mass of Zn= 65.4 g/mol

thus 65.4 g of zinc liberates 1 mol i.e. 22.4 L hydrogen gas at STP

32.65 g of zinc will liberate:

65.4/22.4×32.65=11.18L of hydrogen gas at STP