Question

hydrogen peroxide and water contain 5.93% and 11.2% of hydrogen respectively . show that the data illustrates law of multiple proportions.

Answer 1

in h2O2
H=5.93
O=94.07
again, H=11.2
O=177
In H2O
H=11.2
O=88.8
mass of one element should be same
since the ratio between two O=177:88=1:2
therefore it follows the law of multiple proportion

Answer 2

Answer: % of hydrogen in H2O2=5.93.

% of oxygen in H2O2=100- 5.93=94.07%

And ,

%of hydrogen in H2O =11.2%

%of oxygen in H2O=100-11.2%=88.8%

In H2O2

H:O =5.93:94.07=1:16

In H2O

H:O=11.2:88.8

=1:8

Ratio of oxygen in the H2O2 and H2O= 8:16=1:2

Since the ratio is a whole number the data represents law of multiple proportion.

Explanation: