Question

Hydrogen peroxide in its reaction with KIO4 and NH2OH respectively, is acting as

(a)Reducing Agent,Oxidising
Agent
(b)Reducing Agent,Reducing
Agent
(c)Oxidising Agent,Oxidising
Agent
(d)Oxidising Agent,Reducing
Agent

Answer 1

Answer: The correct answer is Option a.

Explanation:

Oxidizing Agent is defined as the agent which helps the other substance to get oxidized and itself gets reduced. The oxidation state of the oxidizing agent gets reduced.

Reducing Agent is defined as the agent which helps the other substance to get reduced and itself gets oxidized. The oxidation state of the reducing agent is increased.

• Reaction of Hydrogen Peroxide with $KIO_4$ follows the equation:

$H_2O_2+KIO_4\rightarrow KIO_3+H_2O+O_2$

Oxidation state of Iodine on reactant side = +7

Oxidation state of Iodine on product side = +5

As, the oxidation state of iodine is getting reduced, hence it is getting reduced. So, it will act as oxidizing agent and $H_2O_2$ will act as reducing agent.

• Reaction of Hydrogen Peroxide with $NH_2OH$ follows the equation:

$4H_2O_2+2NH_2OH\rightarrow N_2O_3+7H_2O$

Oxidation state of Nitrogen on reactant side = -1

Oxidation state of Nitrogen on product side = +3

As, the oxidation state of nitrogen is increasing, hence it is getting oxidized. So, it will act as reducing agent and $H_2O_2$ will act as oxidizing agent.

So, the correct option is option a.

Answer 2

Answer:

KIO  4  +H 2 O  2  →KIO  3  +H  2  O+O  2

​NH  2 OH+3H 2  O  2  →HNO  3  +4H  2 O.

From this above reaction, we can easily figure out that hydrogen peroxide is acting as reducing and oxidising agent respectively.

Explanation: