Question

Hydrogen reacts with nitrogen to produce ammonia according to this equation: 3h2(g) + n2(g) → 2nh3(g) determine how much ammonia would be produced if 200 g of hydrogen reacts

Answer 1

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Answer 2

Answer:  1133.3 grams

Explanation:

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$  

For $H_2$

Given mass = 200.0 g

Molar mass of  $H_2$ = 2.0 g/mol

Putting values in above equation, we get:

$\text{Moles of}H_2=\frac{200}{2}=100moles$

$3H_2(g+N_2(g)\rightarrow 2NH_3(g)$

3 moles of $H_2$ produces 2 moles of $NH_3$

100 moles of $H_2$ produces =$\frac{2}{3}\times 100=66.7$ moles of $NH_3$

Mass of $NH_3=moles\times {\text {molar mass}}=66.7\times 17=1133.3 g$

Thus 1133.3 g of ammonia would be produced if 200 g of hydrogen reacts.