Hydrolysis of sucrose gives. Sucrose+h2o =glucose +fructose . Equilibrium constant kc for the reaction is 2*10^13 at 300 k calculate ∆g° at 300 k
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The change in Gibb’s free energy is related to the equilibrium constant as:-
G=-RTln(K).
Putting the given values in the above equation
We get
G = -2.303RTlog(2x10^13)
= - 2.303x8.314x300x13.3010
= -76.4028 KJ/mol
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