Question

Hydrostatic pressure in water varies is significantly over small change in depth where as the atmospheric pressure does not change unless the difference in altitude is very large explain why

Answer 1

$\underline{\underline{\Huge\mathfrak{Answer}}}$

Consider a liquid contained in a beaker, such that 'd' is the density of liquid.

Consider a liquid column of height 'h' and area of cross-sectional 'a'.

Let 'B' be a point at the base of this imaginary liquid column as shown in drawing.

Therefore, Volume of imaginary column of liquid = area of cross -sectional × length
= a × h

Therefore, Weight of liquid column = mg = a×h×d×g

Therefore, Pressure due to liquid column P at point B = F/a
= ahdg/ a × P = h×d×g.