Hypotenuse AB= 3x, BC= 3x/2.
Find SIDE AC by pythagoras theorem.
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answe is 3 × root3 x / 2
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Answer:
AC^2= AB^2+BC^2
AC^2=3x^2+3x/2^2
AC^2=9x^2+9x^2/4
=36x^2+9x^2/4
AC^2 =45x^2/4
AC=3×root5x/2
Hope u understand it..
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