hypotenuse of a right angle triangle is 25 cm and its perpendicular distance is 7 cm find the length of its base
chiragmishra25:
24
Answers
Answered by
19
by pythogaras theorem
(h)^2 =(p)^2 + (b)^2
625 = 49 +b^2
underoot 576
24 cm
(h)^2 =(p)^2 + (b)^2
625 = 49 +b^2
underoot 576
24 cm
Answered by
22
hypotenuse=25cm
perpendicular=7cm
base=?
According to Pythagoras theorem
(Hypotenuse) square=(Base) square + (Perpendicular) square
25 square=(Base) square +7square
625= (Base) square +49
(Base) square=625-49
Base √576
Base=24cm
perpendicular=7cm
base=?
According to Pythagoras theorem
(Hypotenuse) square=(Base) square + (Perpendicular) square
25 square=(Base) square +7square
625= (Base) square +49
(Base) square=625-49
Base √576
Base=24cm
Similar questions