Question

Hypotenuse of a right triangle is 25cm and out of remaining two sides . one is longer than the other by 5cm . Find the length of the other two sides .​

Answer 1

Step-by-step explanation:

the other two sides are 15 and 20.

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Answer 2

Step-by-step explanation:

$h = 25cm \\ let \: b = x \: cm \\ according \: the \: question \\ p = x + 5 \: cm \\ pythagoras \: theorem \\ {h}^{2} = {b}^{2} + {p}^{2} \\( 25) {}^{2} = {x}^{2} + (x + 5) {}^{2} \\ 625 = {x}^{2} + {x}^{2} + 25 + 10x \\ 625 = 2 {x}^{2} + 10x + 25 \\ 2 {x}^{2} + 10x - 600 = 0 \\ divide \: by \: 2 \\ {x}^{2} + 5x - 300 = 0 \\ {x}^{2} + (20 - 15)x - 300 = 0 \\ {x}^{2} + 20x - 15x - 300 = 0 \\ x(x + 20) - 15(x + 20) = 0 \\ (x + 20)(x - 15) = 0 \\ if \: x + 20 = 0 \\ x = - 20(invalid) \\ if \: x - 15 = 0 \\ x = 15 \\ then \: b = x = 15 \: cm \\ p = x + 5 = 20 \: cm$