Question

hypotenuse of right triangle =13 cm
perpendicular=12 cm
find base
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Answer 1

Answer:

BASE=5✔✔

Step-by-step explanation:

□H=13 CM✔✔

□P=12 CM✔✔

○B=?

${h}^{2} = {p}^{2} + {b}^{2} \\ {13}^{2} = {12}^{2} + {b}^{2} \\ 169 = 144 + {b}^{2} \\ 169 - 144 = {b}^{2} \\ b = \sqrt{25} \\ b = 5$

Answer 2

$\huge{\boxed{\sf{SOLUTION-}}}$

To find the base of the right angkled traingle, we have to apply one of the property of right angle triangle -

${(hypotenuse)}^{2} = {(altitude)}^{2} + {(base)}^{2}$

Let the base be 'b'.

${(13)}^{2} = {(12)}^{2} + {(b)}^{2}$

$169 = 144 + {b}^{2}$

$169 - 144 = {b}^{2}$

$25 = {b}^{2}$

$\sqrt{25} = b$

$b = \sqrt{25}$

$b = 5$

Hence,

Hence,The base of the right angled triangle is 5 cm.