Question

Hypotheses of an isosceles triangle is 10cm .find other 2sides of the triangle ?​

Answer 1

Since this is a isosceles right triangle, we know we have to use the Pythagorean Theorem: A2 + B2 = C2 , where A and B = the legs of the triangle (which are shorter than the hypotenuse) and C = the hypotenuse.

In this isosceles triangle, A = B (because the legs are the same size) and C is 10cm longer than A and B.

Thus we get the following,

A = x

B = x

C = x + 10

We simply plug in these variables into the equation and solve for x:

x^2 + x2 = (x+10)^2

2x2 = x^2 + 20x + 100

x2 - 20x - 100 = 0

We solve for x by completing the square:

(x^2 - 20x + 100) - 100 = 100

(x-10)^2 -100 = 100

(x-10)^2 = 200

x - 10 = √(200)

x - 10 = 10 √2

x = 10 + 10√2 = 24

Finally,

A = 24 (or 10 + 10√2)

B = 24 (or 10 + 10√2)

C = 24 + 10 = 34 (or 10 + 10√2 + 10 = 20 + 10√2)

Answer 2

Answer:

$\sqrt{50}$

Step-by-step explanation:

square of hypotheses= sum of square of two other sides

so

100=2$x^{2}$

so 50=$x^{2}$

therefore answer is $\sqrt{50}$